Three mass ‘m’ each are kept at corner of a equilateral triangle and are rotating under effect of mutual gravitational force -
A
Radius of circular path followed by mass is a/2
B
Velocity of mass is 
C
Binding energy of system is 
D
Time period of mass is 
Text Solution
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(b, c)
Distance of any mass from center = 
∴ Radius of circular path followed = 
Mass is moving in circular path of radius 
∴ 
= 
⇒ v = 
∴ T = 
= 
Total K.E. = 
= 
P.E. = – 3. 
∴ Total energy = 
. 
∴ B.E. = 
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